Solve the following pair of linear equations by the method of substitution: $2x - 3y = -11$ and $4x - 6y + 22 = 0$.

(N/A) Given equations are:
$1) \, 2x - 3y = -11$
$2) \, 4x - 6y + 22 = 0$
From equation $(2)$,we can write $4x - 6y = -22$,which simplifies to $2(2x - 3y) = -22$,or $2x - 3y = -11$.
Since both equations are identical,they represent the same line.
This means the system has infinitely many solutions.
Any pair $(x, y)$ satisfying $2x - 3y = -11$ is a solution.
Thus,the solution set is $\{(x, y) \mid 2x - 3y = -11; \, x, y \in R \}$.